Ensuring the structure is comfortable for users. This involves calculating deflections (sagging) and vibrations to ensure floors don't bounce excessively under foot traffic. 4. Connections and Detailing
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wD=40 psf×8 ft=320 plf=0.32 klfw sub cap D equals 40 psf cross 8 ft equals 320 plf equals 0.32 klf Ensuring the structure is comfortable for users
DCR=Required StrengthDesign Strength≤1.0DCR equals the fraction with numerator Required Strength and denominator Design Strength end-fraction is less than or equal to 1.0 steel structure design calculation pdf